Need to determine `IS_LABEL_POSSIBLE()` properly.

Otherwise, `{"a": 1}` will cause `SyntaxError`.
parent 79cfa377
......@@ -3974,6 +3974,7 @@ parse_string(parser_state *p)
int end = intn(p->lex_strterm->cdr->cdr->cdr);
parser_heredoc_info *hinf = (type & STR_FUNC_HEREDOC) ? parsing_heredoc_inf(p) : NULL;
int cmd_state = p->cmd_start;
int label_p = IS_LABEL_POSSIBLE();
if (beg == 0) beg = -3; /* should never happen */
if (end == 0) end = -3;
......@@ -4188,7 +4189,7 @@ parse_string(parser_state *p)
return tREGEXP;
}
pylval.nd = new_str(p, tok(p), toklen(p));
if (IS_LABEL_POSSIBLE()) {
if (label_p) {
if (IS_LABEL_SUFFIX(0)) {
p->lstate = EXPR_BEG;
nextc(p);
......
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